Solution 61: Subtle Differences in Conditional Probability (Comparing Polynomials)

  • Published on Oct 11, 2018
  • What was ambiguous in the statement of the problem, and why do two different interpretations yield different answers? Let's find out.
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Comments • 5

  • Shenghui Yang
    Shenghui Yang 10 months ago +1

    Excellent example about conditional probability

  • Rahmed
    Rahmed 10 months ago

    Can you give your email address?
    It's impossible to reach you and I have a hard integral for you to solve

  • Donald Hobson
    Donald Hobson 10 months ago

    In the reals, (x^2+1)*(x-1)^2 also has only one root. Is this poly allowed? What about x^4+1

    • attyfarbuckle
      attyfarbuckle 10 months ago

      In the comments under the challenge video it says to consider these as polynomials over C, the complex numbers.
      So all the polynomials have 4 roots including multiplicity.
      The answer would trivially be zero over the reals.